2y^2+4y+12x+28=0

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Solution for 2y^2+4y+12x+28=0 equation:


Simplifying
2y2 + 4y + 12x + 28 = 0

Reorder the terms:
28 + 12x + 4y + 2y2 = 0

Solving
28 + 12x + 4y + 2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + 12x + 4y + -28 + 2y2 = 0 + -28

Reorder the terms:
28 + -28 + 12x + 4y + 2y2 = 0 + -28

Combine like terms: 28 + -28 = 0
0 + 12x + 4y + 2y2 = 0 + -28
12x + 4y + 2y2 = 0 + -28

Combine like terms: 0 + -28 = -28
12x + 4y + 2y2 = -28

Add '-4y' to each side of the equation.
12x + 4y + -4y + 2y2 = -28 + -4y

Combine like terms: 4y + -4y = 0
12x + 0 + 2y2 = -28 + -4y
12x + 2y2 = -28 + -4y

Add '-2y2' to each side of the equation.
12x + 2y2 + -2y2 = -28 + -4y + -2y2

Combine like terms: 2y2 + -2y2 = 0
12x + 0 = -28 + -4y + -2y2
12x = -28 + -4y + -2y2

Divide each side by '12'.
x = -2.333333333 + -0.3333333333y + -0.1666666667y2

Simplifying
x = -2.333333333 + -0.3333333333y + -0.1666666667y2

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